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What is the pOH of a solution prepared by adding 0.465 g of ammonium bromide to...

What is the pOH of a solution prepared by adding 0.465 g of ammonium bromide to 115 mL of water?  Kb of NH3 is 1.8

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Answer #1

The first step is to calculate the concentration of ammonium bromide (NH4Br). According to the information provided we have 0.465 g of NH4Br dissolved in 115 ml of water, then the molarity is (neglecting the volume of NH4Br added):

Now, we must calculate the concentration of hydrogen ions formed by the following reactions:

In order to calculate the concentration of hydrogen ions we can use the following equation:

Where Kw= 1x10-14. This equation is valid in the case we have solutions constitued by a salt resulting from a weak base and a strong acid like ammonium bromide.

Replacing the values we get:

Then the pH and the pOH of this solution is:

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