Question

Part A-Calculate the mass percent (m/m) of a solution prepared by dissolving 45.05 g of NaCl in 176.2 g of H2O.

Part B- Vinegar is a solution of acetic acid in water. If a 125 mL bottle of distilled vinegar contains 23.2 mL of acetic acid, what is the volume percent (v/v) of the solution?

Part C- Calculate the mass/volume percent (m/v) of 24.0 g NaCl in 52.5 mL of solution.

Part D- Calculate the molarity (M) of 156.6 g of H2SO4 in 1.250 L of solution.

Answer 1

A) we know that

mass percent = mass of solute / ( mass of solute + solvent ) * 100

therefore

mass percent = 45.05 g / ( 45.05 + 176.2 g ) * 100

= 20.36 %

B) volume percent = volume of solute / ( volume of solute + solvent) * 100

= 23.2 ml / ( 23.2 ml + 125 ml ) * 100

= 15.65 %

C) mas/volume percent = mass of solute / volume of solution * 100

= 24 .0 g / 52.5 ml * 100

= 45.71 %

D) molarity = moles / volume in liter

moles of H2SO4 = 156.6 g / 98.079 g/mol

= 1.60 mol

and

molarity = 1.60 mol / 1.25 L

= 1.28 mol/L

= 1.28 M