Question

1. How many grams of Cr²⁺ are present in 1.20 grams of chromium(II) sulfide?
______ grams Cr²⁺.

2. How many grams of chromium(II) sulfide contain 4.32 grams of Cr²⁺?
______grams chromium(II) sulfide.

Answer 1

Answer 1

CrS (Chromium Sulfide) = 1.20g

now as we know

1 mol of CrS have = 1 mol of Cr²⁺

CrS Cr²⁺ + S^2-

molecular mass of CrS = 84

molecular mass of Cr²⁺ = 52

1 mol of CrS have = 1 mol of Cr²⁺

84 g of CrS gives = 52 g of Cr²⁺

1 g of CrS gives = 52 / 84 g Cr²⁺

1.2 g of CrS give = 1.2 * 52 / 84 g of Cr²⁺

= 0.7428 of Cr²⁺

Answer = 0.7428 g of Cr²⁺

Answer 2

grams of Cr²⁺ = 4.32g

molecular mass of CrS = 84

molecular mass of Cr²⁺ = 52

1 mol of Cr²⁺ have = 1 mol of CrS

52 g of Cr²⁺ give = 84 g of CrS

1g of Cr²⁺ give = 84 / 52 g of CrS

4.32 g of Cr²⁺ give = 4.32 * 84 / 52 g of CrS

6.9785 g of CrS

Answer = 6.9785 g of CrS