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The temperature of an ideal gas in a 5.00 L container originally at 1 atm pressure...

The temperature of an ideal gas in a 5.00 L container originally at 1 atm pressure and 25

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I habitually change all temps to K and all volumes to L and all pressures to atm, b/c I had a professor that insisted on it when dealing with the ideal gas law. Also, P=Pressure, P1=initial pressure, P2 =final pressure; V=Volume and T=Temperature - the follow the same rules as P1 and P2.

25C to 220K, pressure changes to .738atm. (initial pressure/initial temp=final pressure/final temp), so 1atm/298.15K=P/220K, therefore (1atm*220K/298.15K=P), solving for P leaves .738 atm.

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