#4 A system containing 2.50 moles of an ideal gas for which = 20.79 JK-1mol-1 is taken through the following cycles: (1) an isobaric expansion (P1 = 16.6 bar) from V1 = 1.00 L to V2 = 25.0 L; (2) an isochoric cooling from T2 to the original temperature, T1; followed by (3) an isothermal compression (at temperature T1) to the original pressure P1 and volume V1.
A. Represent the above processes on a P-V diagram
B. Calculate q, w, ΔU and ΔH for each segment and for the whole cycle.
a)
b)
For Isobaric Expansion,
P = 16.6 bar
V1 = 1 L
V2 = 25 L
T1 = P1V1 / nR = 80.877 K
T2 = P2V2 / nR = 2021.92 K
w = - P (V2 - V1)
w = - 16.6 ( 25 - 1 ) = - 398.4 J
U = nCvT = 2.5 x 20.79 x (2021.92 - 80.877)
U = 100885.943 J
q = U - w = 100885.943 + 398.4 = 101284.34 J
H = nCpT = 2.5 x (20.79+8.314) x (2021.92 - 80.877)
H = 141230.289 J
For Isochoric cooling,
V = 0 = w
q = U = nCvT = 2.5 x 20.79 x (80.877 - 2021.92)
q = U = -100885.943 J
H = nCpT = 2.5 x (20.79+8.314) x (80.877 - 2021.92)
H = -141230.289 J
For Isothermal Compression,
T = 0 = U = H
q = w = nRTln(V2/V1)
q = w = (2.5)(8.314)(80.877)ln(1/25)
q = w = 5411.022 J
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