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Calculate the concentration of a solution of HCl if a 25.00 mL sample required 24.87 mL...

Calculate the concentration of a solution of HCl if a 25.00 mL sample required 24.87 mL of 0.1014 M NaOH to titrate to the endpoint.

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Answer #1

Balanced equation is

NaOH + HCl -----> NaCl + H2O

molarity of NaOH = number of moles of NaOH / volume of solution in L

0.1014 M = number of moles of NaOH / 0.02487 L

number of moles of NaOH = 0.1014 * 0.02487 = 0.002522 mole

from the balanced equation we can say that

1 mole of NaOH requires 1 mole of HCl so

0.002522 mole of NaOH will require 0.002522 mole of HCl

molarity of HCl = number of moles of HCl / volume of solution in L

molarity of HCl = 0.002522 / 0.025 = 0.101 M

Therefore, the concentration of HCl = 0.101 M

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