Question

Under anaerobic conditions, glucose is broken down in muscle tissue to form lactic acid according to the reaction: C6H12O6 → 2 CH3CHOHCOOH

Assume all heat capacities are constant from T = 298 K to T = 310 K.

For glucose, C^o_p,m=218.2JK.mol

For lactic acid, C^o_p,m=127.6JK.mol

Find: parts D, E, F and show work please!

A) Calculate Δ_rH⁰ at T = 298 K. (Answer= -113.8 kJ/mol)

B) Calculate Δ_rS⁰ at T = 298 K. (Answer= 72.42 J/(mol.K) )

C) Calculate Δ_rG⁰ at T = 298 K. (Answer= -135.3 kJ/mol )

D) Calculate Δ_rH⁰ at T = 310 K. (that is,  Δ_rH^o₃₁₀−Δ_rH^o₂₉₈ )

E) Calculate Δ_rS⁰ at T = 310 K. (that is, Δ_rS^o₃₁₀−Δ_rS^o₂₉₈)

F) Calculate Δ_rG⁰ at T = 310 K. (that is,  Δ_rG^o₃₁₀−Δ_rG^o₂₉₈)

Answer 1