Question

A flexible container at an initial volume of 3.10 L contains 2.51 mol of gas. More gas is then added to the container until it reaches a final volume of 18.1 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Answer 1

Given, initial volume, V₁ = 3.10 L and n₁ = 2.51 mol and final volume, V₂ = 18.1 L

We know from ideal gas equation PV= nRT

=> V/n = RT/P

Here R is the universal gas constant and it is also mentioned that T and P are constant here.

Now,

V/n = constant

=> V₁ / n₁ = V₂/n₂ (from Avogadros' law)

=> 3.10 L / 2.51 mol = V₂ / n₂

=> 3.10 L / 2.51 mol = 18.1 L / n₂

=> n₂ = (2.51 x 18.1 / 3.10) mol

=> n₂ =(45.431/3.10) mol

=> n₂ = 14.7 mol in total

Finally. number of moles added = 14.7 mol - 2.51 mol = 12.19 mol = 12.2 mol

Hence, the answer is 12.2 mol.