Question

In an acid-base neutralization reaction, 38.74 mL of 0.500 mol L^-1 potassium hydroxide reacts with 50.00 mL of sulfuric acid solution. What is the concentration of the H₂SO₄ solution?

Answer 1

moles of KOH = Molarity of KOH x volume of KOH in liters = 0.5 mol / L x 0.03874 L = 0.01937 mol

let see the balanced equation

H2SO4 + 2KOH ---> K2SO4 + 2H2O

from this balanced equation

1 mol of KOH required half mole of H2SO4 accordingly

0.01937 mol of KOH required 0.01937 /2 = 0.009685 mol H2SO4

moles of H2SO4 = 0.009685 mol

volume of H2SO4 = 50.0 mL convert in to L = 0.05 L

Molarity of H2SO4 = mol of H2SO4 / volume of H2SO4 = 0.009685 mol / 0.05 L = 0.1937 mol /L