Question

If Bryce had 5.00 quarts of water in an adiabatic container at room tempereature, 298K, how much ice will he need to add to bring the temperature to 0 degree celcius

Answer 1

Mass of water = 5.00 quarts = 5.00 * 946.353 g = 4731.765 g.

specific heat of water = 4.184 J/K.g

initial temperature = 298 K

final temperature = 273 K

heat change, q = 4731.765 * 4.184 * (298 - 273) = 494942.62 J = 495.0 kJ

specific heat of fusion of ice = 334j/g = 0.334 kJ/g

0.334 kJ of heat is absorbed by 1 g. of ice during its fusion

then, 495.0 kJ of heat is absorbed by = 1 * 495.0 / 0.334 =1482 g. of ice.

SO, we need to 1.482 kg of ice to bring the temperature to 0 degree C