Question

A 40.0 mL sample of 0.400M NaOH is titrated with 0.200M HNO3 at 25 degrees C....

A 40.0 mL sample of 0.400M NaOH is titrated with 0.200M HNO3 at 25 degrees C. Calculate the pH when 40.0 mL of titrant has been added to the system.

Homework Answers

Answer #1

Here is the Solution:

Thanks! :-)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
40.0 ml of 0.600M hydrofluoric acid, HF, is titrated with 0.400M sodium hydroxide, NaOH. Calculate the...
40.0 ml of 0.600M hydrofluoric acid, HF, is titrated with 0.400M sodium hydroxide, NaOH. Calculate the pH of the solution after the addition of 35.0 ml of NaOH solution.
A 25.00 mL sample of 0.280 M NaOH analyte was titrated with 0.750 M HCl at...
A 25.00 mL sample of 0.280 M NaOH analyte was titrated with 0.750 M HCl at 25 °C. Calculate the initial pH before any titrant was added. ​Calculate pH after 5.0 ml of titrant was added
A 40.0 mL sample of 0.150 M Ba(OH)2 is titrated with 0.400 M HNO3. Calculate the...
A 40.0 mL sample of 0.150 M Ba(OH)2 is titrated with 0.400 M HNO3. Calculate the pH after the addition of the following volumes of acid. a) 0.0 mL b) 15.0 mL c) At the equivalence point d) 40.0 mL
25.000 mL of 0.1114 M propanoic acid solution is titrated with 0.1308 M NaOH. Calculate the...
25.000 mL of 0.1114 M propanoic acid solution is titrated with 0.1308 M NaOH. Calculate the pH of titrant mixture at the following volumes of NaOH added a) 12.72 mL b) 21.29 mL (Equivalence point)
A 40.0 mL volume of 0.100 M NaOH is titrated with 0.0500 M HCl. Calculate the...
A 40.0 mL volume of 0.100 M NaOH is titrated with 0.0500 M HCl. Calculate the pH after addition of the following volumes of acid. 1.) 64 mL 2.) 89.4 mL 3.) 92 mL
A 20.0 mL of 0.20 M HNO3 was titrated with 10.0 mL of 0.20 M NaOH....
A 20.0 mL of 0.20 M HNO3 was titrated with 10.0 mL of 0.20 M NaOH. Determine the pH of the solution and record below with correct significant figures.
A 25.0 mL sample of an acetic acid solution in titrated with a 0.09984 M NaOH...
A 25.0 mL sample of an acetic acid solution in titrated with a 0.09984 M NaOH solution. The equivalence point is reached when 37.5 mL of the base is added. Calculate the concentration of acetic acid in the 25.0 mL sample. Calculate the pH at the equivalence point (Ka acetic acid = 1.75x10^-5)
A 25 mL aliquot of an HCl solution is titrated with 0.100 M NaOH. The equivalence...
A 25 mL aliquot of an HCl solution is titrated with 0.100 M NaOH. The equivalence point is reached after 21.27 mL of the base were added. Calculate the concentration of the acid in the original solution, the pH of the original HCl solution and the original NaOH solution
In a titratiom 0.140 M Hbr is titrated by 0.100 M NaOH. If 16.00 mL of...
In a titratiom 0.140 M Hbr is titrated by 0.100 M NaOH. If 16.00 mL of the NaOH titrant is added to 20.00 mL of the HBr solution (followed by mixing). What is the pH of the resulting solution?   A. 2.30 B. 1.48 C. 4.60 D. 1.84 E. 1.20
When 100.0 mL of a weak acid was titrated with 0.09381 M NaOH, 27.63 mL were...
When 100.0 mL of a weak acid was titrated with 0.09381 M NaOH, 27.63 mL were required to reach the equivalence point. The pH at the equivalence point was 10.99. What was the pH when only 19.47 mL of NaOH had been added?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT