Question

Ammonia is burned to form nitric oxide in the following reaction: 4NH3 + 5O2 ----> 4NO...

Ammonia is burned to form nitric oxide in the following reaction: 4NH3 + 5O2 ----> 4NO + 6H2O

The Fractional conversion of oxygen is 0.500 and the inlet flow rates of NH3 is 10 mol/h

Oxygen is supplied using air (assume 79:21 - N2:O2) fed to reactor at rate of 710 g/h

(a) How much oxygen is fed to the reactor (in mol/h)?

(b) Which reactan is in excess and by how much (in %)?

(c) Calculate the exit molar flow rates of all compounds (in mol/h)

Homework Answers

Answer #1

(a)

The air has average molar mass of 29 g/mol.

Air is fed to reactor at rate of 710 g/h. This corresponds to

Assume 79:21 - N2:O2

Hence O2 is fed to reactor at rate of

(b)

The flow rates of ammonia and O2 are 10 mol/h and 5.14 mol/h respectively.

10 mol/h ammonia will react with O2 however only 5.14 mol/h O2 is present. Hence, O2 is the limiting reactant and NH3 is excess reactant.

% Excess of %

(c) The Fractional conversion of oxygen is 0.500. So the exit molar flow rate of

The exit molar flow rate of NO

The exit molar flow rate of

The exit molar flow rate of

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
4NH3 + 5O2 --> 4NO + 6H2O 1. Nitric acid is made by first reacting ammonia...
4NH3 + 5O2 --> 4NO + 6H2O 1. Nitric acid is made by first reacting ammonia and oxygen to form nitric oxide: NH3 (g)+O2 (g)⟶NO(g)+H2O(g) Calculate the heat of reaction at a) standard conditions (this is what the book calls ∆ ) and b) at 500 °C. (This is what the book calls ∆ ) 2. (Builds off of problem 1). Ammonia gas enters a reactor with 30% more dry air (no water vapor) than is required for complete conversion....
topic: Species and Elemental Balances 1.Ammonia is burned to form nitric oxide and water: 4??3+5?2→4??+6?2?4〖NH〗_3+5O_2→4NO+6H_2 O...
topic: Species and Elemental Balances 1.Ammonia is burned to form nitric oxide and water: 4??3+5?2→4??+6?2?4〖NH〗_3+5O_2→4NO+6H_2 O The fractional conversion of oxygen is 0.500. The inlet molar flow rate is 52.5 mol/h of NH3 and 5.00 mol/h of oxygen gas. Calculate the exit component molar flow rates.
Consider the chemical equation. 4NH3+5O2⟶4NO+6H2O4NH3+5O2⟶4NO+6H2O When 26 g of ammonia burn in 26 g of oxygen,...
Consider the chemical equation. 4NH3+5O2⟶4NO+6H2O4NH3+5O2⟶4NO+6H2O When 26 g of ammonia burn in 26 g of oxygen, what is the limiting reagent? NH3NH3 and O2O2 NONO O2O2 H2OH2O NH3NH3
Modern processes for the production of nitric acid are based upon the oxidation of ammonia synthesized...
Modern processes for the production of nitric acid are based upon the oxidation of ammonia synthesized via the Haber reaction. The first step of the oxidation process is the reaction of NH3 with O2 over a platinum catalyst to produce nitric oxide: 4NH3 + 5O2 ------> 4NO + 6H2O Under a given set of reactor conditions, 90% conversion of NH3 is obtained with a feed of 40 moles/hr NH3 and 60 moles/hr O2. (a) What is the limiting reactant? (b)...
Ammonia reacts with oxygen according to the equation: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g)ΔHrxn=−906kJ. Calculate the heat (in kJ) associated with...
Ammonia reacts with oxygen according to the equation: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g)ΔHrxn=−906kJ. Calculate the heat (in kJ) associated with the complete reaction of 215 g of NH3.
Ammonia reacts with oxygen according to the equation: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g) ΔHrxn=-906 kJ Part A Calculate the heat...
Ammonia reacts with oxygen according to the equation: 4NH3(g)+5O2(g)→4NO(g)+6H2O(g) ΔHrxn=-906 kJ Part A Calculate the heat (in kJ) associated with the complete reaction of 284 g of NH3.
Ammonia gas enters a reactor with 30% more dry air (no water vapor) than is required...
Ammonia gas enters a reactor with 30% more dry air (no water vapor) than is required for complete conversion (4NH3 + 5O2 --> 4NO + 6H2O). These gases enter the reactor at 75c and exit at 600c. How much heat is required per mole of ammonia fed?
The gas phase equilibrium reaction is exothermic : 4NH3(g)+5O2(g) <----->4NO(g)+6H2O(g) What is the effect of each...
The gas phase equilibrium reaction is exothermic : 4NH3(g)+5O2(g) <----->4NO(g)+6H2O(g) What is the effect of each of the following? A) Decreasing the volume B) increasing/adding H2O C) increasing the temperature D) removing some oxygen E) increasing/adding NH3 F) adding a catalyst
1.) Consider the reaction: 4NH3 + 5O2 → 4NO + 6H2O In an experiment, 4.45 g...
1.) Consider the reaction: 4NH3 + 5O2 → 4NO + 6H2O In an experiment, 4.45 g of NH3 are allowed to react with 6.50 g of O2. How many grams of NO are formed?    a.) 6.09 g NO     b.) 4.88 g NO     c.) 7.84 g NO     d.) 8.13 g NO 2.) Given the following reaction: AgNO3 (aq)+ NaI (aq) → AgI (s) + NaNO3 (aq) How many grams of AgI  will be produced from 15.0 g of...
The Ostwald process for the commercial production of nitric acid from ammonia and oxygen involves the...
The Ostwald process for the commercial production of nitric acid from ammonia and oxygen involves the following steps: 4NH3(g)+5O2(g)------->4NO(g)+6H2O(g) -908 kj/mol (delta H) 2NO(g)+O2(g)----------->2NO2(g) -112 kj/mol 3NO2(g)+H2O(l)-------->2HNO3(aq)+NO(g) -140 kj/mol Write the overall equation for the production of nitric acid by the Ostwald process by combining the preceding equations (Water is also a product). So i know the answer is this... "Multiply the equations so that the coefficients of the N-products become the same as the N-educts of the following line....
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT