A (aq) ---> B (aq) ΔG standard for rxn = 4.13 kJ
A reaction vessel was charged with a compound A (4.11 M) and compound B (6.71 M) and allowed to react at 225 K. After a period of 6.7 hours, ΔG was determined to be 1.11 kJ. What was the concentration of compound A at that time?
A (aq) B (aq)
Go = 4.13 kJ
G = 1.11 kJ
Temperature, T = 225 K
Since, Go is positive, backward reaction will be spontaneous.
So, B
(aq) A (aq)
Initial
6.71
4.11
Final 6.71 -
x
4.11 + x
Using equation,
G = Go + RTlnQ
1.11 = 4.13 + 8.314X10-3*225 ln (6.71 - x / 4.11 + x)
- 3.02 = 1.8706 ln(6.71 - x / 4.11 + x)
ln(6.71 - x / 4.11 + x) = - 1.6144
(6.71 - x / 4.11 + x) = - 0.199
Solving this we get:
x = 1.83 M
Hence, the concentration of compound A after 6.7 hours = 4.11 + 1.83
= 5.94 M
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