Question

Calculate the ΔG∘rxn for the reaction using the following information.

4HNO3(g)+5N2H4(l)→7N2(g)+12H2O(l)

ΔG∘f(HNO3(g)) = -73.5 kJ/mol;
ΔG∘f(N2H4(l)) = 149.3 kJ/mol;
ΔG∘f(N2(g)) = 0 kJ/mol;
ΔG∘f(H2O(l)) = -273.1 kJ/mol.

Calculate the  for the reaction using the following information.



= -73.5 ;
= 149.3 ;
= 0 ;
= -273.1 .

-312.9 kJ

+110.7 kJ

-954.7 kJ

-3.298 x 10³ kJ

+2.845 x 10³ kJ

Answer 1

               4HNO3(g)+5N2H4(l)→7N2(g)+12H2O(l)

ΔG∘rxn   = (7*ΔG∘f(N2(g)) + 12*ΔG∘f(H2O(l))) -(4*ΔG∘f(HNO3(g))+5*ΔG∘f(N2H4(l)))

              = (7*0 +12*-273.1)-( 4*-73.5 +5*149.3)

              = -3277.2-452.5

            = -3729.7KJ/mole    = -3.7297*10³ Kj/mole >>> answer