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a student titrates a 25.00mL aliquot of HCl (concentration unknown) with 33.10mL of 0.1500M NaOH. What...

a student titrates a 25.00mL aliquot of HCl (concentration unknown) with 33.10mL of 0.1500M NaOH. What is the concentration of HCl?

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Answer #1

molarity of NaOH = number of moles of NaOH / volume of solution in L

0.1500 M = number of moles of NaOH / 0.0331 L

number of moles of NaOH = 0.1500 *0.0331 = 0.004965 mole

Balanced equation is

NaOH + HCl -----> NaCl + H2O

from the balanced equation we can say that

1 mole of NaOH requires 1 mole of HCl so

0.004965 mole of NaOH will require 0.004965 mole of HCl

molarity of HCl = number of moles of HCl / volume of solution in L

molarity of HCl = 0.004965 / 0.025 L = 0.199 M

Therefore, the concentration of HCl = 0.199 M

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