Question

# A certain weak base has a Kb of 8.50 × 10-7. What concentration of this base...

A certain weak base has a Kb of 8.50 × 10-7. What concentration of this base will produce a pH of 10.23?

PH = 10.23

POH =14-PH

= 14-10.23

= 3.77

POH   = 3.77

-log[OH-] = 3.77

[OH-] = 10-3.77    = 1.69*10-4 M

[OH-] = Kb*C

1.69*10-4   = 8.5*10-7 *C

1.69*10-4 * 1.69*10-4    = 8.5*10-7 *C

C                                = 1.69*10-4 * 1.69*10-4/ 8.5*10-7

= 3.36*10-2 M

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