Question

A certain weak base has a Kb of 8.50 × 10-7. What concentration of this base will produce a pH of 10.23?

Answer #1

PH = 10.23

POH =14-PH

= 14-10.23

= 3.77

POH = 3.77

-log[OH-] = 3.77

[OH-] = 10^{-3.77}
= 1.69*10^{-4} M

[OH-] = Kb*C

1.69*10^{-4} = 8.5*10^{-7}
*C

1.69*10^{-4} * 1.69*10^{-4} =
8.5*10^{-7} *C

C
= 1.69*10^{-4} * 1.69*10^{-4}/
8.5*10^{-7}

= 3.36*10^{-2} M

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