Question

A 7.76-L cylinder contains 1.69 mol of gas A and 4.15 mol of gas B, at a temperature of 33.3 °C. Calculate the partial pressure of each gas in the cylinder. Assume ideal gas behavior.

What is the total pressure?

Answer 1

1)

Given:

V = 7.76 L

n = 1.69 mol

T = 33.3 oC

= (33.3+273) K

= 306.3 K

use:

P * V = n*R*T

P * 7.76 L = 1.69 mol* 0.08206 atm.L/mol.K * 306.3 K

P = 5.474 atm

Answer: partial pressure of A = 5.47 atm

2)

Given:

V = 7.76 L

n = 4.15 mol

T = 33.3 oC

= (33.3+273) K

= 306.3 K

use:

P * V = n*R*T

P * 7.76 L = 4.15 mol* 0.08206 atm.L/mol.K * 306.3 K

P = 13.442 atm

Answer: partial pressure of B = 13.4 atm

3)

total pressure = p(A) + p(B)

= 5.47 atm + 13.4 atm

= 18.9 atm

Answer: 18.9 atm