Question

Consider the following redox reaction:

5Fe2+(aq)+MnO−4(aq)+8H+(aq)→5Fe3+(aq)+Mn2+(aq)+4H2O(l)

Part A - What is the oxidation state of iron before the reaction?

Part B - What is the oxidation state of manganese before the reaction?

Part C - What is the oxidation state of hydrogen before the reaction?

Part D - What is the oxidation state of oxygen before the reaction?

Part E - What is the oxidation state of iron after the reaction?

Part F - What is the oxidation state of manganese after the reaction?

Part G - What is the oxidation state of hydrogen after the reaction?

Part H - What is the oxidation state of oxygen after the reaction?

Enter an integer

Answer 1

A)

Oxidation state of Fe in Fe2+ is +2

Answer: +2

B)

Oxidation number of O = -2

lets the oxidation number of Mn be x

use:

4* oxidation number (O) + 1* oxidation number (Mn) = net charge

4*(-2)+1* x = -1

-8 + 1 * x = -1

x = 7

So oxidation number of Mn = +7

Answer: +7

C)

Oxidation state of H in H+ is +1

Answer: +1

D)

Oxidation state of O in MnO4 is -2

Answer: -2

E)

Oxidation state of Fe in Fe3+ is +3

Answer: +3

F)

Oxidation state of Mn in Mn2+ is +2

Answer: +2

G)

Oxidation state of H in H2O is +1

Answer: +1

H)

Oxidation state of O in H2O is -2

Answer: -2