Question

For the balanced reaction of: N₂ + 3H₂ → 2NH₃. What is the mass of the excess reagent when 84.06g of N₂ and 22.18g of H₂ are combined?

Answer 1

molar mass of N₂ = 28.013 gm /mole

molar mass of H₂ = 2.01 therefore 3 mole of H₂ = 2.01 3 = 6.03 gm

According to reaction 1 mole of N₂ react with 3 mole of H₂ that mean 28.013 gm of N₂ react with 6.03 gm of H₂ then for to react with 84.06 gm of N₂ required H₂ = 84.06 6.03 / 28.013 = 18.09 gm of H₂ required

but H₂ given 22.18 gm and required is 18.09 therefore 22.18 - 18.09 = 4.09 gm of H₂ is excess reagent.