Question

Use the volume at the equivalence point of 16 mL from the second titration to determine the Molarity of the H2O2 solution.

Answer 1

the volume of equivalence point= 16 mL = 0.16L

the density of H₂O₂ = 1.1 g/ml

from electrochemcial series, the standard reduction potential in aqueous solution at 25^oC = 1.763 V

i.e, H₂O₂ ​(aq) + 2H⁺(aq) + 2e^- 2H₂O(l)

so , number of moles = 2

the molarity of H₂O₂ ​= number of moles X volume of equivalence point (in Liters)

                                  = 2 X 0.16

                                 =     0.32 mols/L

hence , the Molarity of the H₂O₂ ​ solution = 0.32 M