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Consider 3Fe+2 —> 2Fe+3 + Fe Calculate E and determine if this is a spontaneous or...

Consider 3Fe+2 —> 2Fe+3 + Fe

Calculate E and determine if this is a spontaneous or non-spontaneous reaction.

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Answer #1

3Fe2+ → 2Fe3+ +Fe

The half cell reactions are

Fe2+ + 2e →Fe               reduction (cathode)                E0 = -0.44 V

Fe2+ → Fe3+ +1e         oxidation (anode)               E0 = -0.77 V

E0cell = E0 cathode-E0 anode = -0.44-0.77 = -1.21 V

Since E0cell is negative, the reaction is non spontaneous

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