Question

If 1.33 moles of an ideal gas has a pressure of 3.53 atm, and a volume of 38.49 L, what is the temperature of the sample in degrees Celsius?

Answer 1

Ideal gas equation

PV = nRT             where, P = atm pressure= 3.53 atm

V = volume in Liter = 38.49 L

n = number of mole = 1.33 mol

R = 0.08205L atm mol^-1 K^-1 =Proportionality constant = gas constant,

T = Temperature in K = ?

We can write ideal gas equation

T = PV/nR

substitute the value in above equation

T = 3.5338.49/1.330.08205

T = 1245.066 K

1245.066K = 1245.066 - 273.15 = 971.916 ⁰C

tempreture of sample = 971.916⁰C