If 1.33 moles of an ideal gas has a pressure of 3.53 atm, and a volume of 38.49 L, what is the temperature of the sample in degrees Celsius?
Ideal gas equation
PV = nRT where, P = atm pressure= 3.53 atm
V = volume in Liter = 38.49 L
n = number of mole = 1.33 mol
R = 0.08205L atm mol-1 K-1 =Proportionality constant = gas constant,
T = Temperature in K = ?
We can write ideal gas equation
T = PV/nR
substitute the value in above equation
T = 3.5338.49/1.330.08205
T = 1245.066 K
1245.066K = 1245.066 - 273.15 = 971.916 0C
tempreture of sample = 971.9160C
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