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The reaction 2H2O2(l)=2H2O(l) + O2(g) is found experimentally to follow first-order kinetics with a rate constant...

The reaction 2H2O2(l)=2H2O(l) + O2(g) is found experimentally to follow first-order kinetics with a rate constant of 0.030s-1. The concentration of peroxide, H2O2(l) after 25s is found to be 0.010M. What was the intial concentration of H2O2(l) from these data?

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Answer #1

2H2O2(l)--------->2H2O(l) + O2(g)

K   = 0.030s^-1

t   = 25s

[A]   = 0.01M

[A0]   =

K   = 2.303/t log[A0]/[A]

0.030 = 2.303/25 log[A0]/0.010

log[A0]/0.010   = 0.030*25/2.303

log[A0]/0.010    = 0.3256

[A0]/0.010        = 10^0.3256

[A0]/0.010        = 2.1164

[A0]                 = 2.1164*0.01

[A0]                 = 0.21164M

the intial concentration of H2O2(l) is 0.21164M

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