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upon heating 125 g MgSO4 ×7H2O how many grams of water can be obtained

upon heating 125 g MgSO4 ×7H2O how many grams of water can be obtained

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Answer #1

Reaction of question can be written as follows

MgSO4 : 7H2​O -----> MgSO4 + 7H2O

125 gms of MgSO4 : 7H2​O heated

Molecular weight of = 246.47g/moles

Dividing 125g with molecular weight will give moles

Moles of MgSO4 : 7H2O = 125/ 246.47 = 0.507 moles

Now one mole of MgSO4 is associated with 7 moles of H2O

Therefore molesof H2O = 7x 0.507 = 3.549 moles of H2O.

Mass of water (gms)=molecular weight of water x moles ofwater = 18x 3.549 = 63.882 gms

So, 63.882 gms of water can be obtainedby heating 125 gms of MgSO4:7H2O

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