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Why Is the Joule-thompson coefficient of Helium calculated using the van der Waals equation more accurate...

Why Is the Joule-thompson coefficient of Helium calculated using the van der Waals equation more accurate than the one calculated by the Beattie-Bridgeman equation, while Joule-thompson coefficient of Argon calculated using then the Beattie-Bridgeman equation is more accurate?

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Answer #1

For Helium gas intermolecular force of attraction is very small and the corresponding constant "a" in van der Waal's equation is also very small.

Therefore it will give only negative value for the Joule-Thomson coefficient as given by the following equation.

  

The first and last term will be close to zero.

The bettie bridgemann equation contains five constants in addition to "R" universal gas constant. Since for Argon gas both "a" and "b" values are significant in the calculation of Joule-Thomson coefficient, this equation will be more accurate than van der Waal's equation.

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