Question

# A flask is charged with 1.800atm of N2O4(g) and 1.00 atm NO2(g) at 25 ?C, and...

A flask is charged with 1.800atm of N2O4(g) and 1.00 atm NO2(g) at 25 ?C, and the following equilibrium is achieved: N2O4(g)?2NO2 After equilibrium is reached, the partial pressure of NO2 is 0.512atm . Calculate Kc for the reaction.

N2O4(g)<------>2NO2
initial                        1.8                   1
at equilibrium            1.8-x                1+2x

given partial pressure of NO2= 0.512 atm
so,1+2x=0.512
x= -0.244

p(N2O4) = 1.8 - x = 1.8 + 0.244 = 2.044 atm

Kp = 0.512 ^2 / 2.044
=0.1283

Kc = Kp /(R*T)^delta n
= 0.1283 / (0.0821 * 298)^1
=5.242 *10^-3

#### Earn Coins

Coins can be redeemed for fabulous gifts.

##### Need Online Homework Help?

Most questions answered within 1 hours.

##### Active Questions
• An Engineering consultant appointed on the construction of a Bridge site decided to conduct the Plate...
• Create a program in java using if statements Suppose the WIFI of a client is not...
• W Mart, one of major retailers, reported cash flows and earning: Comprehensive income) for the firm...
• Parker Hi-Fi Systems Parker Hi-Fi Systems, located in Wellesley, Massachusetts, a Boston suburb, assembles and sells...
• Manufacturing companies strive to maintain production​ consistency, but it is often difficult for outsiders to tell...
• There is a difference between statistical probability and theoretical probability. The theoretical probability of rolling a...