Question

1. How many electrons are in the ion Cr2+?

2. Which species functions as the oxidizing agent in the following reduction-oxidation reaction:     Ba(s) + Hg²⁺(aq) → Hg(l) + Ba²⁺(aq)

3. If the melting point of iridium metal is 2989 K, what is its melting point in degrees Celcius?

4.Which of the compounds HNO₃, Ba(OH)₂, CsOH, and HBr, behave as acids when they are dissolved in water?

Please quick answers

Answer 1

1. number of electrons in Cr = 24

number of electrons in Cr2+ = 24-2 = 22 electrons

2. The oxidation number of Ba is changing from 0 to +2 and Hg from +2 to 0. So, Ba is being oxidised and Hg is being reduced. Thus Ba is acting as reducing agent and Hg is acting as oxidising agent.

3. melting point = 2989 K = 2989-273 ^oC = 2716 ^oC

4. HNO₃, HBr release H⁺ when dissolved in water and Ba(OH)₂ and CsOH release OH^- in water. Thus HNO₃ and HBr behaves as acids and Ba(OH)₂ and CsOH behave as bases.