An aqueous solution containing a substance whose concentration is 7.50 g/L has an osmotic pressure of 1150 Torr at 77 K.
(a) What is the molecular weight of the solute?
(b) What is the osmotic pressure of a solution at 27 degrees C that contains 1.00 g of this solute in 500 mL of solution?
PV = nRT
P = 1150torr = 1150/760 = 1.513atm
W = 7.5g
V = 1L
T = 77K
PV = WRT/M
M = WRT/PV
= 7.5*0.0821*77/1.513*1 = 31.34g/mole
b. PV = nRT
PV = WRT/M
W = 1g
M = 31.34g/mole
T = 27C = 27+273 = 300K
V = 500ml = 0.5L
PV = WRT/M
P = WRT/VM
= 1*0.0821*300/0.5*31.34 = 1.57atm
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