The change in entropy of the system and the universe if one mole of argon is expanded isothermally and reversible at 300. K from 10.0 L to 20.0 L.
assuming the expansion is free. Calculate:
a) entropy of the system in J/K
b) entropy of the universe in J/K
Please explain each step.
a) For reversible isothermal process with free expansion the change in entropy of the system is given by the formula.
N = 1 mole , V2 = 20 , V1 = 10
= 1 * 8.31447 * ln ( 20/10 ) = 8.31447 * ln(2) = 5.763 J/K.
b) Entropy of the Universe = entropy of the system + entropy of the surroundings
Entropy of the surroundings in a free expansion is 0 as there is no interaction between system and surroundings.
so Entropy of Universe = Entropy of the system
= 5.763 J/K.
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