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Vapor Pressures of a solid and liquid ammonia near the triple point are given by: log...

Vapor Pressures of a solid and liquid ammonia near the triple point are given by: log P solid/ torr=10.00-1630 K/T log P liquid / torr=8.46-1330 K/T Calculate the ratio of the slopes of the sublimation and vapor pressure curves at the triple point.

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Answer #1

using Clausius-clapeyron equation , ln P/solid=ln A+ -Hfus/R(1/T) (for solid)

or, 2.303 log P/solid=ln A+ -Hfus/R(1/T)

or,log P/solid=1/2.303 ln A+ -Hfus/2.303 R(1/T)

So ,from log P solid/ torr=10.00-1630 K/T  

slope*2.303 R=-Hfus=1630*2.303 R

Also,log P/liquid=1/2.303 ln A+ -Hvap/2.303 R(1/T) (for liquid)

log P liquid / torr=8.46-1330 K/T

slope*2.303R=-Hvap=1330*2.303 R

Hsublimation=Hfus+Hvap=1330*2.303 R+1630*2.303R=2960*2.303R

log P/sub =1/2.303 log A-Hsublimation/2.303 R(1/T)

or,log P/sub =1/2.303 log A-2960/ R(1/T)

ratio of slope of sub to vapour pressure of solid=2960/1630=1.816

ratio of slope of sub to vapour pressure of liquid=2960/1330=2.225

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