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The combustion of octane, C8H18, proceeds according to the reaction, If 3.70 × 102 mol of...

The combustion of octane, C8H18, proceeds according to the reaction, If 3.70 × 102 mol of octane combusts, what volume of carbon dioxide is produced at 19.0 °C and 0.995 atm?

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Answer #1

2C8H18 + 25 O2 18H2O +16CO2

this ia the balanced reaction for combution of octane

2 mole of C8H18 give 16 mole of CO2

one mole octane give 8mole CO2

3.70102 =377.4 mole octane produce 377.48 =3019.2 mole CO2

according to avogadros law 1 nole gas occupy volume 22.414 L at STP

so 3019.2 mole gas occupy volume 3019.222.414 =67672.34 L volume at STP

hence at 190C &0.995 atm volume is given as follow

P1V1/T1=P2V2/T2

167672.34/273.15 =0.995V2/292.15

V2=67672.34292.15/273.150.995 =72743.26

volume occupy by CO2 at 190C & 0.995 atm Pressure is 72743.26 liter

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