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Suppose you have an alkaline buffer consisting of 0.20M aqueous ammonia (NH3) and 0.10M ammonium chloride...

Suppose you have an alkaline buffer consisting of 0.20M aqueous ammonia (NH3) and 0.10M ammonium chloride (NH4Cl). What is the ph of the solution?

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Answer #1

   0.20M aqueous ammonia (NH3)

0.10M ammonium chloride (NH4Cl)

POH   = Pkb + log[NH4Cl]/[NH3]

              =4.74 + log0.1/0.2

              = 4.74-0.3010

               = 4.439

   PH     = 14-POH

            = 14-4.439   = 9.561 >>>> answer

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