What are Eo cell and ΔGo of a redox reaction at 25°C for which n = 1 and K = 5.5069?
K = 5.5069
T =25 + 273 = 298K
n = 1
ΔGo =-RTlnK
ΔGo = -8.314*298ln5.5069
= -8.314*298*1.7060
= -4226.74J
ΔGo = -nE0cell*F
-4226.74 = -1*E0cell*96500
E0cell = 4226.74/96500 = 0.0438v
E0cell = 0.0438v >>>>answer
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