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In a combination reaction, if 1.35569 moles of magnesium is heated with 0.3695 moles of nitrogen,...

In a combination reaction, if 1.35569 moles of magnesium is heated with 0.3695 moles of nitrogen, to form magnesium nitride, how many grams of magnesium nitride will be produced?

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Answer #1

The formula of magnesium nitride is

As per balanced chemical equation, 3 moles of Mg reacts with 1 mole of N2.

0.3695 moles of N2 will react with moles of Mg. But 1.35569 moles of Mg are present. Hence, Mg is excess reagent and N2 is limiting reagent.

1 mole of N2 produces 1 mole of Mg3N2. 0.3695 moles of N2 will produce 0.3695 moles of Mg3N2.

Molar mass of Mg3N2 is 100.9 g/mol.

Mass of Mg3N2

.Hence, 37.28 grams of magnesium nitride will be produced.

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