In a combination reaction, if 1.35569 moles of magnesium is heated with 0.3695 moles of nitrogen, to form magnesium nitride, how many grams of magnesium nitride will be produced?
The formula of magnesium nitride is
As per balanced chemical equation, 3 moles of Mg reacts with 1 mole of N2.
0.3695 moles of N2 will react with moles of Mg. But 1.35569 moles of Mg are present. Hence, Mg is excess reagent and N2 is limiting reagent.
1 mole of N2 produces 1 mole of Mg3N2. 0.3695 moles of N2 will produce 0.3695 moles of Mg3N2.
Molar mass of Mg3N2 is 100.9 g/mol.
Mass of Mg3N2
.Hence, 37.28 grams of magnesium nitride will be produced.
Get Answers For Free
Most questions answered within 1 hours.