a. Your product research director wants you to prepare 1 liter of a buffer solution of pH 6.5 having a buffer capacity of 0.10 using a combination of NaH2PO4 and Na2HPO4. What is the exact concentration of each constituent required for this preparation? Ka (NaH2PO4) = 6.2 x 10-8.
Solution:
pKa is calculated as,
pka = - log ka = - log 6.2 x 10^-8
pka = 8 - log 6.2 = 8 - 0.79 = 7.21
According to Hendersen- Hasselbalch equation,
pH = pka + log [Na2HPO4] / [NaH2PO4]
6.5 = 7.21 + log [Na2HPO4] / [NaH2PO4]
log [Na2HPO4] / [NaH2PO4] = -0.71
[Na2HPO4] / [NaH2PO4] = antilog - 0.71 = 0.195 = 0.2
Thus,
[Na2HPO4] = 0.2 x [NaH2PO4]
Therefore,
For preparation of 0.10 buffer capacity,
The concentrations will be:
[Na2HPO4] = 0.2 x 0.10 = 0.02 M
[NaH2PO4] =1 x 0.10 = 0.10 M
Get Answers For Free
Most questions answered within 1 hours.