Question

How many molecules (not moles) of NH3 are produced from 8.97×10−4 g of H2?

Express your answer numerically as the number of molecules.

Answer 1

The balanced reaction is

N2 + 3H2 -----> 2NH3

Given mass of H=8.97x10^-4 g

And molar mass of H2=2.016 g/mol

Therefore moles of H2=mass/molar mass=8.97x10^-4 g/2.016 g/mol=4.449 x 10^-4 mol.

From the balanced equation moles of NH3 formed=(2/3) moles of H2=(2/3)x4.449x10^-4 mol

Moles of NH3=2.966 x 10^-4 mol.

Since 1 mol=6.023x10^23 molecules, then

Molecules of NH3=(6.023x10^23 molecules x 2.966x10^-4 mol)/1 mol

Molescules of NH3 formed=1.786x10^20 molecules.

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