Question

how many g of Fe3O2 (molecular weight: 159.70)are formed by the complete reaction of 6.75 moles or iron?

Answer 1

The balanced chemical reaction is :

4 Fe(s) + 3 O₂(g) 2 Fe₂O₃(s)

Given : moles Fe reacted = 6.75 mol

moles Fe₂O₃ formed = (moles Fe reacted) * (molar ratio of Fe₂O₃ to Fe)

moles Fe₂O₃ formed = (moles Fe reacted) * (2 moles Fe₂O₃ / 4 moles Fe)

moles Fe₂O₃ formed = (6.75 mol) * (2 / 4)

moles Fe₂O₃ formed = (6.75 mol) * (0.5)

moles Fe₂O₃ formed = 3.375 mol

mass Fe₂O₃ formed = (moles Fe₂O₃ formed) * (molar mass Fe₂O₃)

mass Fe₂O₃ formed = (3.375 mol) * (159.70 g/mol)

mass Fe₂O₃ formed = 539 g