The following cross is performed: AaBBCc X AaBBCc
How many offspring would have this genotype? aaC-BB?
Write your answer like this 1/2...
Cross was performed between
Parents AaBBCc × AaBBCc
Gametes :- ABC , ABc , aBC , aBc
Punnett square :-
F⬇️/M➡️ | ABC | ABc | aBC | aBc |
ABC | AABBCC | AABBCc | AaBBCC | AaBBCc |
ABc | AABBCc | AABBcc | AaBBCc | AaBBCc |
aBC | AaBBCC | AaBBCc | aaBBCC | aaBBCc |
aBc | AaBBCc | AaBBcc | aaBBCc | aaBBcc |
The number of offsprings having genotype aaBBC_ is 3.
Total no. Of offsprings = 16
The offspring having Genotype aaBBC_ =
NB:- If it isis specified that the Genotype is either aaBBCC then it will be 1/16 or Genotype is aaBBCc then it will be 2/16= 1/8.
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