Question

A mouse sperm of genotype a FGHY fertilizes an egg of genotype a fghy. What are all the possibilities for the genotypes of (a) the zygote and (b) a sperm or egg of the baby mouse that develops from this fertilization?

Answer 1

Answer:

a.) Zygote: FfGgHhYy

b.) sperm or egg: Total 16 gametes- FGHY, FGHy, FGhY, FGhy, FgHY, FgHy, FghY, Fghy, fGHY, fGHy, fGhY, fGhy, fgHY, fgHy, fghY, fghy

Explanation:

When FGHY is crossed with fghy

FGHY x fghy = FfGgHhYy (zygote) as the cross will produce one genotype for the zygote.

There are four heterozygotes Ff, Hh, Gg and Yy

So the number of different gametes would be

2 ^ heterozygotes

2^4=16

or else you can use product rule

Ff x Gg x Hh x Yy
2 x 2 x x 2 x 2 = 16 gametes.

- Follow the below diagram in order to find possible gametes or else you can find out manually the possible combinations by product rule to build the same.

- We obtain such results as the inheritance of one gene is independent of the other.