Question

3) In general, p = allele frequency of the dominant allele and q = allele frequency of the recessive allele. Using the product and/or sum rule(s), use these variables (p and q) to determine the probabilities of an individual in the next generation being:

a) Homozygous dominant (A dominant allele (A) AND another dominant allele (A))?

b) Homozygous recessive (A recessive allele (a) AND another recessive allele (a))?

c) Heterozygote (Aa OR aA)?

4a) In a population in Hardy-Weinberg equilibrium, there are 100 total individuals. If 36 display the recessive trait, how many of individuals are homozygous dominant?

b) How many are heterozygotes?

Answer 1

A) The homozygous dominant genotype is AA. There is found two dominant alleles. The probbaility is calculated by : (p)^2

B) Homozygous recessive genotype is aa. There is found two recessive allele. The probbaility is calculated by: (q)^2

C) Heterozygoys genotype is Aa. The probability is 2×p×q

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Answer 4)

the 36 individuals have recessuve trait.

Genotypic frequency of aa= 36/100= 0.36

Allelic frequency of recssive allele (p) is √0.36= 0.6

Allelic frequency of dominant allele p is 1- q= 1- 0.6=0.4

A) Homozygous dominant individuals number are: (p) ^2×100= (0.4) ^2×100=0.16×100=16

B) Heterozygoys individuals are :2 ×p×q×100= 2×0.4×0.6×100= 48

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