Question

Flowers need only 20% of the enzyme produced in wild type to have pink color. A...

Flowers need only 20% of the enzyme produced in wild type to have pink color. A mutant allele is recessive to wild type because the heterozygotes have enough enzyme for pink color flowers. A double mutant does not make enough enzyme for pink flower color and results in a white flower color. Biochemical tests show no activity at all of the mutant enzyme and the enzyme is missing its active site. What type of mutation is this?

hypermorphic mutation

hypomorphic mutation

neomorphic mutation

null mutation

Homework Answers

Answer #1

The answer will be null mutation (Last option).

Explanation: Hypermorphic mutation is a gain-of-function mutation in which normal gene function increased. If this type of mutation occurred then we will observed increase activity of the enzyme. In hypomorphic mutation, wild type gene activity occurred at reduced level. In neomorphic mutation, a novel molecular function is gained. So, we can ignore first three options. In null mutation, wild type enzyme activity is not observed as enzyme become non-functional. Thus, correct answer will be last option.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A tiger color variant with a white coat and black stripes occurs due to an autosomoal...
A tiger color variant with a white coat and black stripes occurs due to an autosomoal recessive mutation in a transport protein. Homozygous dominant individuals (genotype DD) have wild-type orange coloration. Heterozygotes (Dd) also have the wild-type coloration but are carriers for the white allele. Homozygous recessive individuals (dd) have the white phenotype A population of tigers has a recessive allele frequency of 0.2. What proportion of the tigers are expected to be heterozygous carriers if the population is in...
Morning glory plants homozygous for the F allele have pink flowers. What is a likely consequence...
Morning glory plants homozygous for the F allele have pink flowers. What is a likely consequence of the F allele mutation? A. It likely increases CHS mRNA degradation B. *It likely reduces the level of CHS transcription C. It likely causes a CHS enzyme with reduced function to be produced D. It likely disrupts splicing of the CHS pre-mRNA E. It likely causes an increase in CHS enzyme production
Consider a hypothetical flower called the Purple Beauty whose wild-type phenotype consists of dark purple pigmentation....
Consider a hypothetical flower called the Purple Beauty whose wild-type phenotype consists of dark purple pigmentation. The purple pigment is the product of a biosynthetic pathway involving a number of enzymatic steps in which a colorless precursor compound, P, is sequentially converted into two intermediate molecules, I(1) and I(2), and then into the final product, the dark purple pigment, DP. The following is a diagram of this biosynthetic pathway, where gene A is responsible for the production of enzyme A,...
In golden retrievers, the D/d gene codes for an enzyme that produces a pigment. The dominant...
In golden retrievers, the D/d gene codes for an enzyme that produces a pigment. The dominant allele (D) results in a golden pigment, while the recessive allele (d) codes for red pigment. Additionally, the V/v gene produces a transport protein responsible for depositing the pigment produced by D/d into the hair. When the dominant V allele is present, the color expressed by D/d will be deposited and the dog will be that color (golden or red). However, allele v is...
1. A species of flowering plant includes plants with blooms that range from bright golden yellow...
1. A species of flowering plant includes plants with blooms that range from bright golden yellow to very pale yellow; no flowers carrying the yellow pigment allele appear white. The allele for yellow flower color: a. must be a suppressor of another allele. b. demonstrates incomplete penetrance. c. demonstrates variable expressivity. d. must be a modifier of another allele. e. demonstrates variable penetrance. 2. Coat color in mice is determined by two alleles acting at a single locus: B is...
Match the term to the description. Ex 1 = E Terms 1. Alagille                                &n
Match the term to the description. Ex 1 = E Terms 1. Alagille                                                                             Cystic Fibrosis Cri du chat Sickle Cell disease klinefelter syndrome WilliamSyndrome Jacob’s Syndrome X-linked Poly-X female Trisomy 21 Gene Linkage Down Syndrome Turner’s Syndrome Deletion Inversion Duplication 17.Fragile x syndrome 18.Hemophilia   Muscular Dystrophy Color blindness   Achondroplasia independent assortment Huntington Neurofibromatosis 25.Phenylketonuria Tay-Sachs Burkett lymphoma Mendel’s Law of Segregation Mendel’s Law of Independent Assortment Incomplete Dominance Multiple Allelic Traits 32.Polygenic Inheritance 33.Polyploidy 34.Aneuploidy Amniocentesis Chorionic Villi Sampling...