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You are working with a mutant coli strain for which 1 incorrect nucleotide is incorporated every...

You are working with a mutant coli strain for which 1 incorrect nucleotide is incorporated every ~104 added nucleotides during replication. Further investigation of this E. coli reveals that the unusually high error rate for replication results from a mutation of a DNA polymerase. Which of the choices below is the most likely explanation for your data?

The 5’ → 3’ polymerase activity of pol III has been eliminated.

The 3’ → 5’ polymerase activity of pol III has been eliminated.

The 3’ → 5’ exonuclease activity of pol III has been eliminated.

The 5’ → 3’ polymerase activity of pol I has been eliminated.

The ligase activity of pol I has been eliminated.

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Answer #1

Answer is :

The 3’ → 5’ exonuclease activity of pol III has been eliminated.

DNA polymerase III is the main replicating enzyme in the the replication process. DNA polymerase 1 is the the repair enzyme in the process of replication. It removes the mutant base pair from the DNA and synthesizes new wild-type nucleotide at this position. The 3' to 5' exonuclease activity helps in the process.

it also fills the gap which is created by removing the okazaki segment.

The DNA polymerase 3 has both exonuclease activity. That's why answer is DNA polymerase 3 exonuclease activity is deleted.

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