If a plant that is homozygous for the recessive mutation that inactivates enzyme 1 is crossed with a plant that is homozygous for the recessive mutation that inactivates enzyme 2, what are the expected phenotypes of the F1 progeny? Choose the best answer.
white - enzyme 1 - blue - enzyme 2 - red
All F1 progeny will be Red.
As the recessive mutation are only expressed when the alleles are present in homozygous condition and when there are present in heterozygous conditions no effects of recessive mutation is seen. Suppose in the above case a red homozygous plant which is dominant is crossed with a blue plant which has the alleles rr all red plants are produced due to present of dominant gene R and no inactivation of enzyme responsible for red color is seen as alleles should be homozygous to inactivate the action of gene. Blue being recessive its color is masked by red gene.
RR(Red) x rr (Blue)
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