Question

You carry out an F2 cross (with a male heterozygote and a female heterozygote) for this...

You carry out an F2 cross (with a male heterozygote and a female heterozygote) for this gene, which we will call “Eyeless” or “e”. You get the following progeny: 2/3 of the drosophila are wild-type phenotype (e+), 1/3 of the drosophila are small eyes phenotype (e). Which of the following genetics best explains your results?

Group of answer choices

Eyeless is autosomal dominant with a heterozygote advantage.

Eyeless is codominant.

Eyeless is autosomal recessive with a lethal allele.

Eyeless is autosomal recessive with a heterozygote advantage.

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Answer #1

homozygous eyeless mutants have small or reduced eyes.

heterozygotes are normal.

eyeless is homozygous recessive, the dominant allele at the Eyeless locus is E, homozygous for E allele is lethal, that is Drosophilia with EE genotype is not viable.

E- dominant allele e- recessive allele

Ee * Ee

E e
E EE ( not viable) Ee (normal eyes)
e Ee ( normal eyes) ee ( small eyes)

the phenotypic ratio is

normal eyes: small eyes=2:1

here heterozygotes have normal eyes also they are viable so the answer is d) Eyeless is autosomal recessive with a heterozygote advantage.

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