You carry out an F2 cross (with a male heterozygote and a female heterozygote) for this gene, which we will call “Eyeless” or “e”. You get the following progeny: 2/3 of the drosophila are wild-type phenotype (e+), 1/3 of the drosophila are small eyes phenotype (e). Which of the following genetics best explains your results?
Group of answer choices
Eyeless is autosomal dominant with a heterozygote advantage.
Eyeless is codominant.
Eyeless is autosomal recessive with a lethal allele.
Eyeless is autosomal recessive with a heterozygote advantage.
homozygous eyeless mutants have small or reduced eyes.
heterozygotes are normal.
eyeless is homozygous recessive, the dominant allele at the Eyeless locus is E, homozygous for E allele is lethal, that is Drosophilia with EE genotype is not viable.
E- dominant allele e- recessive allele
Ee * Ee
|E||EE ( not viable)||Ee (normal eyes)|
|e||Ee ( normal eyes)||ee ( small eyes)|
the phenotypic ratio is
normal eyes: small eyes=2:1
here heterozygotes have normal eyes also they are viable so the answer is d) Eyeless is autosomal recessive with a heterozygote advantage.
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