In mice, black hair "B" is dominant to brown hair "b", and smooth coat "S" is dominant to rough coat "s".
Cross a brown, rough coated mouse, with a brown, homozygous smooth coated mouse.
a. What are the genotypes of the parents?
b. What is the expected genotypic ratio of the offspring?
c. What is the expected phenotypic ratio of the offspring?
Answer:
a.) genotype of parents:
Brown, rough coated :
bbss
brown, homozygous smooth coated: bbSS
b.) Genotypic ratio: 16:0 (1:0)
c.) Phenotypic ratio: 16:0 (1:0)
Explanation:
Allele:
B: Dominant (black hair)
b: recessive (brown hair)
S: Dominant (Smooth coat)
s: recessive (rough coat)
Genotype:
BB: homozygous dominant
Bb: heterozygous
bb: homozygous recessive
SS: homozygous dominant
Ss: heterozygous
ss: homozygous recessive
Phenotype:
BB: black hair
Bb: black hair
bb: brown hair
SS: smooth coat
Ss: smooth coat
ss: rough coat
a.) genotype of parents:
Brown, rough coated :
bbss
brown, homozygous smooth coated: bbSS
- Now, make a punnett square of cross of bbss x bbSS.
bs | bs | bs | bs | |
bS | bbSs | bbSs | bbSs | bbSs |
bS | bbSs | bbSs | bbSs | bbSs |
bS | bbSs | bbSs | bbSs | bbSs |
bS | bbSs | bbSs | bbSs | bbSs |
b.) Genotypic ratio: 16:0
Genotype | Count | Percentage |
bbSs | 16 | 100% |
c.) Phenotypic ratio: 16:0
Phenotype | Count | Percentage |
brown, smooth coated | 16 | 100% |
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