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A rare disease due to a recessive allele that is lethal when homozygous occurs with a...

A rare disease due to a recessive allele that is lethal when homozygous occurs with a frequency of one in a million. How many individuals in a town of 1,400 can be expected to carry this allele?

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Answer #1

The question follows hardy weinberg equilibrium.

(p+q)2 = p2 + 2pq + q2 = 1

p2 = Homozygous dominant (AA)

2pq = Heterozygous (Aa)

q2 = homozygous recessive (aa)

According to question, a rare disease due to a recessive allele that is lethal when homozygous occurs with a frequency of one in a million, So

aa = q2 = 0.000001 = 1/1000000

q = 0.001

p = 0.999

2pq = 2(0.001)(0.999)

= 0.001998

Number of individuals in a town of 1,400 expected to carry the allele = 0.001998 x 1400

= 2.79

= 3 individuals

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