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The sepia (se) eye mutation is a non-lethal recessive mutation located on chromosome III in Drosophila...

The sepia (se) eye mutation is a non-lethal recessive mutation located on chromosome III in Drosophila (it is not sex-linked, the sex chromosome is chromosome I). Predict the results of a monohybrid cross (F2 generation) with the following parents: a homozygous wild- type female fly and a male fly with sepia eyes. Use a se+ for wild type and se for the mutation. What are the Parental genotypes? ________ The F1 genotypes? _______ Draw a Punnett square to determine the predicted phenotypic ratios in the F2 generation.

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Answer #1

The genotypes of the parents are:

Male parent - seseXY

Female parent - se+se+XX

The F1 cross would like:

seX seY
se+X sese+XX sese+XY
se+X sese+XX sese+XY

From the above cross, we can see that the F1 genotypes are sese+XX and sese+XY

By crossing the results of F1 generation, we get:

seX seY se+X se+Y
seX seseXX (F, sepia) seseXY (M, sepia) sese+XX (F, wild type) sese+XY (M, wild type)
se+X sese+XX (F, wild type) sese+XY (M, wild type) se+se+XX (F, wild type) se+se+XY (M, wild type)

We determine the phenotypic ratio in the above cross as 1:3:3:1

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