Question

**What is activated sludge? How it is different from
primary sludge?**

Answer #1

What is activated sludge? How it is different from
primary sludge?

What is activated sludge? How it is different from
primary sludge?

Mass of solids Generated from the activated sludge tanks.
13. Assume: The total design flow is 3.75 MGD (15,000
m3/day). The NPDES limit is 25/30. Assume that the waste
strength is 170 mg/L BOD after primary
clarification. Y = 0.55 kg/kg.
What is the mass of solids generated each day (Kg/day or
lbs/day) in the activated sludge tankage?

If the F/M of a 0.44 m3/s completely mixed activated
sludge plant is 0.20 mg/mg.d, the influent BOD5 after
primary settling is 180 mg/L, and the MLVSS is 3,200 mg/L,
Calculate the following:(you can assume any missing data)
The volume of the aeration tank?
The HRT
The cell residence time
The recirculated sludge
The waste activated sludge produced each day from the plant in
kg/d
The mass of oxygen to be supplied (kg/d).

A wastewater plant with the activated sludge process received 5
× 106 L/day of wastewater with a BOD5 of 500
mg/L. The primary clarifier removes 30% of the BOD and primary
clarify effluent has no biomass (Xi=0 mg/L). Recycle
(Qr) and waste sludge (Qw) flows are 25% and
2% of Qin, respectively. Effluent BOD5 from secondary
clarifier and waste sludge is 20 mg/L. Microorganism concentration
in the waste sludge (Xw) is 6,000 mg/L. Soluble
BOD5 is biologically converted into CO2...

An activated sludge system with recycle (CMFR) uses to treat
primary effluent after sedimentation.Use the appropriate kinetic
coefficients for the influent water characteristics to CMFR.
Influent Characteristics: Flow = 1000 m3/day; bsCOD= 192 g/m3;
nbVSS= 30 g/m3; inert inorganics= 10 g/m3
Aeration Tank Data: MLVSS = 2500; g/m3; SRT or θc = 6-day
Calculate:
1.- Effluent bsCOD
2.- Hydraulic retention time
3.- Daily sludge production in Kg/day as
a) VSS
b)TSS

Design a completely mixed activated sludge process using three
different design approaches (i.e. calculate the volume of the
aeration basin). Base your design for the first approach on
detention time, for the second one on BOD loading, and the third
one on kinetics. The influent design flow rate to the activated
sludge process is 10,000 m3 /day with a BOD5 concentration of
200mg/L. Completely mixed activated sludge processes typically have
a detention time ranging from 3 to 6 hours and...

F/M ratio is the equilibrium parameter for activated sludge
systems . It is the balance between food substrate and
microorganisms.If the F/M of a 0.4380 m3/sec activated sludge plant
is 0.2 mg/mg-d (inlet BOD 150 mg/l. sludge 2,200 mg/l) what is the
required volume of the aeration tank? What can the plant operator
do to maintained an acceptable F/M if the inlet volume increases by
20%?

Identify two unit process used to thicken waste activated sludge
and describe how each process functions.

How is suspended solids and sludge different?
What is the relationship between them?

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