Question

Depolarization of axolema during nerve conduction takes place because of (a) equal amount of Na+ and...

Depolarization of axolema during nerve conduction takes place because of

(a) equal amount of Na+ and K+ move out across axolema

(b) Na+ move inside and K+ move more outside.

(c) more Na+ outside

(d) none of the above

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Answer #1

Membrane channels are open for positive ion flow into the cell, that is increases the flow of sodium inside the cell that cause depolarization.

Steps if transmission of impulse is

1. Resting potential 2. Depolarization 3. Action potential 4. Repolarization.

Action potential begin when depolarization increased. Repolarization is flow of sodium inside the cell to generate optimun voltage for action potential.

Repolarization is flow of potassium ion outside the cell, this drop the voltage inside the cell.

Hence option D is correct.

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