Given, A couple each with blood type AB and normal pigmentation have a child with AB blood type and albinism.
Let, allele A represent normal skin pigment which is dominant over allele a (responsible for albinism).
Genotype of father:
Gametes:
Genotype of mother:
Gametes:
Genotype of daughter:
Cross:
Probability of having a next child with phenotype = 2/16 = 1/8.
Get Answers For Free
Most questions answered within 1 hours.